Answers
<div ng-init="friends = [
{name:'John', age:25, gender:'boy'},
{name:'Jessie', age:30, gender:'girl'},
{name:'Johanna', age:28, gender:'girl'},
{name:'Joy', age:15, gender:'girl'},
{name:'Mary', age:28, gender:'girl'},
{name:'Peter', age:95, gender:'boy'},
{name:'Sebastian', age:50, gender:'boy'},
{name:'Erika', age:27, gender:'girl'},
{name:'Patrick', age:40, gender:'boy'},
{name:'Samantha', age:60, gender:'girl'}
]">
I have {{friends.length}} friends. They are:
<input type="search" ng-model="q" placeholder="filter friends..." />
<ul class="example-animate-container">
<li class="animate-repeat" ng-repeat="friend in friends | filter:q">
[{{$index + 1}}] {{friend.name}} who is {{friend.age}} years old.
</li>
</ul>
</div>
手册例子↑
木头lai了
answered 9 years, 2 months ago
在
ng-repeat
中，使用
d in data
，可以遍历数组中的每一个成员，如果成员本身就是一个直接的数据，则可以直接使用
d
来显示，如果成员还是一个对象，可以使用
d.id
的方法，来访问成员的各个成员。当然，如果直接显示
d
对象，将会以 JSON 的方式来显示。
<script>
$scope.data = [
{id: 0, name: "Sid"},
{id: 1, name: "SegmentFault"},
{id: 2, name: "Github"},
{id: 3, name: "Gitcafe"},
{id: 4, name: "Coding.NET"},
];
</script>
<body>
<p ng-repeat="d in data">id: {{d.id}}, name: {{d.name}}</p>
</body>
smallblack
answered 9 years, 2 months ago